Chapter 24: Optical Fiber Communications
Source: Saleh and Teich, Fundamentals of Photonics, second edition, Chapter 24.
This chapter contains end-of-chapter problems but no boxed in-text exercises.
End-of-chapter problems
Problem 24.1-1 — Assessing fiber-system claims
Brief solution
1. Method. The working uses trigonometric and small-angle identities.
Show detailed steps
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses trigonometric and small-angle identities.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses trigonometric and small-angle identities.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses the physical definitions stated in the item; no separate calculus or algebraic identity is required for this qualitative comparison.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Detailed step 1. (a) 1300 nm usually beats 870 nm for silica loss and modal bandwidth,
Detailed step 2. but cheap short plastic/multimode links can favor 870 nm. (b) 1550 nm has the lowest silica loss and supports EDFAs,
Detailed step 3. while 1300 nm can have lower dispersion in ordinary fiber and cheaper components. (c) Single-mode fiber removes modal dispersion; its advantage is not inherently a lower material attenuation. (d) Material and waveguide dispersion may cancel near 1312 nm,
Detailed step 4. but source linewidth,
Detailed step 5. polarization-mode dispersion,
Detailed step 6. and higher-order dispersion remain. (e) Compound semiconductors are needed for efficient 1.3/1.55-micrometre sources,
Detailed step 7. not for passive fiber,
Detailed step 8. and silicon detectors work near 870 nm. (f) APDs add excess multiplication noise,
Detailed step 9. yet their internal gain can overcome receiver circuit noise and improve sensitivity.
Detailed step 10. Thus none of the six absolute claims is universally true.
Check. For a qualitative conclusion, test every absolute statement against the stated assumptions and at least one limiting case or counterexample.
Check. The zero-angle or paraxial limit supplies an independent sign and magnitude check whenever that limit is part of the model.
Check. The zero-angle or paraxial limit supplies an independent sign and magnitude check whenever that limit is part of the model.
Problem 24.1-2 — Choosing compatible components
Brief solution
1. Method. The working uses trigonometric and small-angle identities.
Show detailed steps
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses trigonometric and small-angle identities.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses trigonometric and small-angle identities.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Definitions and setup. No new mathematical symbols are introduced. Technical terms retain their chapter definitions, and each comparison is conditional on the wavelength, material, geometry, and operating assumptions stated below.
Mathematical formulas used. The working uses the physical definitions stated in the item; no separate calculus or algebraic identity is required for this qualitative comparison.
Worked derivation. Evaluate each claim or design choice against the applicable physical definition, then state the assumption that controls the conclusion.
Detailed step 1. (a) Use a narrow-linewidth 1550-nm InGaAsP laser,
Detailed step 2. single-mode low-loss (often dispersion-managed) silica fiber,
Detailed step 3. EDFAs,
Detailed step 4. and an InGaAs p-i-n or APD receiver. (b) A visible/870-nm LED,
Detailed step 5. plastic or large-core multimode fiber,
Detailed step 6. and silicon p-i-n diode minimize cost; no amplifier is needed. (c) A common 500-Mb/s LAN choice is an 850-nm VCSEL,
Detailed step 7. graded-index multimode fiber,
Detailed step 8. and silicon p-i-n receiver. (d) For temperature margin over 1 km,
Detailed step 9. choose a stabilized 1310-nm InGaAsP laser,
Detailed step 10. silica fiber operated near its zero-dispersion band,
Detailed step 11. and an InGaAs p-i-n receiver; the laser’s narrow spectrum avoids temperature-driven LED linewidth penalties.
Check. For a qualitative conclusion, test every absolute statement against the stated assumptions and at least one limiting case or counterexample.
Check. The zero-angle or paraxial limit supplies an independent sign and magnitude check whenever that limit is part of the model.
Check. The zero-angle or paraxial limit supplies an independent sign and magnitude check whenever that limit is part of the model.
Problem 24.2-1 — Plastic-fiber distance
Brief solution
1. Method. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. The 1-mW source is 0 dBm.
Detailed step 2. After two 3-dB couplers,
Detailed step 3. the fiber may consume \(0-6-(-20)=14\) dB.
Detailed step 4. At 0.5 dB/m, \(\boxed{L_{max}=28\ \mathrm m}\).
Numbered result. The principal result obtained in the working is
Check. Equation (1) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Converting the final decibel value back to a linear power ratio checks the logarithm, sign, and accumulated loss budget. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.2-2 — LED-link distance with two receivers
Brief solution
1. Method. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. Photon-per-bit sensitivity converts through \(P_r=N_ph(hc/\lambda)R_b\).
Detailed step 2. At 10 Mb/s the p-i-n value is \(\boxed{-49.42\ \mathrm{dBm}}\); its loss budget after 4-dB couplers and 6-dB margin permits six whole 1-km segments (21 dB fiber plus five dB of connectors),
Detailed step 3. so \(\boxed{L=6\ \mathrm{km}}\).
Detailed step 4. The APD value is \(\boxed{-65.45\ \mathrm{dBm}}\) and similarly permits \(\boxed{L=10\ \mathrm{km}}\).
Numbered result. The principal result obtained in the working is
Check. Equation (2) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Converting the final decibel value back to a linear power ratio checks the logarithm, sign, and accumulated loss budget. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.2-3 — Attenuation-limited bit rate
Brief solution
1. Method. The working uses expectation, variance, and probability identities, power and decibel conversions, and exponential, logarithmic, and phasor identities.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses expectation, variance, and probability identities, power and decibel conversions, and exponential, logarithmic, and phasor identities.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. The 50-km fiber,
Detailed step 2. fixed losses,
Detailed step 3. and margin consume \(10+8+6=24\) dB,
Detailed step 4. leaving \(7.962\ \mu\mathrm W\).
Detailed step 5. Dividing by 1000 photon energies per bit at 1550 nm gives \(\boxed{R_b=62.1\ \mathrm{Gb/s}}\) at BER \(10^{-9}\).
Detailed step 6. Under the ideal Poisson scaling,
Detailed step 7. changing BER to \(10^{-11}\) multiplies the photon requirement by \(\ln(1/2\times10^{-11})/\ln(1/2\times10^{-9})=1.230\),
Detailed step 8. giving \(\boxed{50.5\ \mathrm{Gb/s}}\).
Numbered result. The principal result obtained in the working is
Check. Equation (3) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. For a probability result, verify the zero-to-one bounds; when a full distribution is present, also verify normalization and nonnegative variance. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.2-4 — Analog APD link
Brief solution
1. Method. The working uses expectation, variance, and probability identities, power and decibel conversions, and algebraic rearrangement and dimensional checks.
2. Key step.
The sinusoidal signal mean square is \((G\mathcal RmP)^2/2\); APD shot-noise variance is \(2eBG^2F\mathcal RP\). Their ratio gives
3. Answer.
Internal gain cancels in this photon-noise-limited case. The 100-microwatt source supplies 15.91 dB of fiber loss, hence \(\boxed{L=6.36\ \mathrm{km}}\).
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses expectation, variance, and probability identities, power and decibel conversions, and algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
The sinusoidal signal mean square is \((G\mathcal RmP)^2/2\); APD shot-noise variance is \(2eBG^2F\mathcal RP\). Their ratio gives
Internal gain cancels in this photon-noise-limited case. The 100-microwatt source supplies 15.91 dB of fiber loss, hence \(\boxed{L=6.36\ \mathrm{km}}\).
Check. Equation (4) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. For a probability result, verify the zero-to-one bounds; when a full distribution is present, also verify normalization and nonnegative variance. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.2-5 — Dispersion time budget
Brief solution
1. Method. The working uses algebraic rearrangement and dimensional checks.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. Ordinary fiber broadens by \(t_f=D_\lambda L\Delta\lambda=340\) ps.
Detailed step 2. The fiber-only criterion gives \(R_b\le0.25/t_f=\boxed{0.735\ \mathrm{Gb/s}}\).
Detailed step 3. Root-sum-square with 20-ps source and 100-ps receiver gives \(t_s=355.0\) ps and the system criterion \(R_b\le0.70/t_s=\boxed{1.97\ \mathrm{Gb/s}}\).
Detailed step 4. With \(D_\lambda=1\), \(t_f=20\) ps and \(t_s=103.9\) ps,
Detailed step 5. giving \(\boxed{12.5\ \mathrm{Gb/s}}\) and \(\boxed{6.74\ \mathrm{Gb/s}}\),
Detailed step 6. respectively.
Numbered result. The principal result obtained in the working is
Check. Equation (5) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Check that dimensions agree term by term, then test the simplest symmetry or limiting case for the expected sign and scale. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.3-1 — WDM channels in C and O bands
Brief solution
1. Method. The working uses algebraic rearrangement and dimensional checks.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. Use frequency,
Detailed step 2. not wavelength,
Detailed step 3. span: \(\Delta\nu=c(1/\lambda_{min}-1/\lambda_{max})\).
Detailed step 4. The C band spans 4.382 THz and the O band 17.495 THz.
Detailed step 5. Counting both endpoint slots gives \(\boxed{\lfloor\Delta\nu/75\ \mathrm{GHz}\rfloor+1=59}\) C-band and \(\boxed{234}\) O-band carriers (58 and 233 are the corresponding numbers of 75-GHz intervals).
Numbered result. The principal result obtained in the working is
Check. Equation (6) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Check that dimensions agree term by term, then test the simplest symmetry or limiting case for the expected sign and scale. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.3-2 — Broadcast-star node limit
Brief solution
1. Method. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
2. Reasoning and answer.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses power and decibel conversions and algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Detailed step 1. A source-to-receiver route traverses two 2-km fiber legs (1.2 dB),
Detailed step 2. two 1-dB connector losses, 3-dB star excess loss,
Detailed step 3. and a 5-dB margin.
Detailed step 4. From a 0-dBm source to a -35-dBm receiver, \(10\log_{10}N\le35-1.2-2-3-5=23.8\) dB.
Detailed step 5. Therefore \(N\le239.9\) and \(\boxed{N_{max}=239}\) whole nodes.
Detailed step 6. If the stated 1-dB connector loss is intended for the entire end-to-end route rather than per star leg,
Detailed step 7. the same budget gives 301 nodes.
Numbered result. The principal result obtained in the working is
Check. Equation (7) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Converting the final decibel value back to a linear power ratio checks the logarithm, sign, and accumulated loss budget. Repeat the substitution with unrounded intermediate values and retain the displayed units; the final unit must have the requested dimension.
Problem 24.3-3 — Six-channel four-node ring
Brief solution
1. Method. The working uses algebraic rearrangement and dimensional checks.
2. Key step.
Regard the six wavelengths as the six edges of a complete graph on four nodes; each node drops its three incident edges. With node 1 assigned \(\{\lambda_1,\lambda_2,\lambda_3\}\), a valid allocation is
3. Answer.
Every node pair shares exactly one channel and no third node drops that channel, so intermediate nodes pass it through.
Show detailed steps
Definitions and setup. Symbols are local to this item and follow the chapter convention. Each physical quantity and supplied numerical value is introduced at its first use below; angles are in radians unless a degree symbol is shown, and units are retained through numerical substitution.
Mathematical formulas used. The working uses algebraic rearrangement and dimensional checks.
Worked derivation. The calculation is kept in symbolic form until the governing relation has been rearranged for the requested quantity.
Regard the six wavelengths as the six edges of a complete graph on four nodes; each node drops its three incident edges. With node 1 assigned \(\{\lambda_1,\lambda_2,\lambda_3\}\), a valid allocation is
Every node pair shares exactly one channel and no third node drops that channel, so intermediate nodes pass it through.
Check. Equation (8) can be checked by substituting it back into the preceding governing relation and reversing the algebraic steps. Check that dimensions agree term by term, then test the simplest symmetry or limiting case for the expected sign and scale.